Find the angles between the pairs of straight lines
`y= 3x+ 7 and 3y- x= 8`

Answer

To find the angle between the two straight lines given by the equations \( y = 3x + 7 \) and \( 3y - x = 8 \), we can follow these steps:

### Step 1: Convert the second equation to slope-intercept form
The second equation is given as \( 3y - x = 8 \). We need to rearrange it to the form \( y = mx + c \).

1. Start with the equation:
\[ 3y - x = 8 \]
2. Rearranging gives:
\[ 3y = x + 8 \]
3. Dividing by 3:
\[ y = \frac{1}{3}x + \frac{8}{3} \]