Find the equation to the straight line
passing through the point (2, 3) and perpendicular to the straight line `4x- 3y= 10`.

Answer

To find the equation of the straight line passing through the point (2, 3) and perpendicular to the line given by the equation \(4x - 3y = 10\), we can follow these steps:

### Step 1: Find the slope of the given line
The equation of the line is given in the standard form \(Ax + By + C = 0\). We can rearrange the equation \(4x - 3y = 10\) to the slope-intercept form \(y = mx + c\).

1. Rearranging gives:
\[ -3y = -4x + 10 \]
\[ y = \frac{4}{3}x - \frac{10}{3} \]

2. From this, we can identify the slope \(m_1\) of the line:
\[ m_1 = \frac{4}{3} \]