Prove that the equation to the straight line which passes through the point `(a cos^(3) theta, a sin^(3) theta)` and is perpendicular to the straight line `x sec theta + y cosec theta= a` is `x cos theta- y sin theta= a cos 2 theta`.

The equation to the straight line passing through the point (a "cos"^(3) theta, a "sin"^(3) theta) and perpendicular to the line x "sec" theta + y"cosec" theta = a is

The equation to the straight line passing through the point (a cos^(3)theta,a sin^(3)theta) and perpendicular to the line x sec theta+y csc theta=a is x cos theta-y sin theta=a cos2 thetax cos theta+y sin theta=a cos2 thetax sin theta+y cos theta=a cos2 theta none of these

Equation of the line passing through the point (acos^3theta, a sin^3theta) and perpendicular to the line xsectheta + y cosec theta =a is xcostheta-ysintheta =acos2theta .

Find the equation of the straight line through (a cos theta, b sin theta) perpendicular to the line x/(a cos theta)+ y/(b sin theta) = 1 .

If x cos theta + y sin theta =2 is perpendicular to the line x-y =3 then what is one of the value of theta ?

(cosec theta-sin theta)(sec theta-cos theta)=sin theta. cos theta