Home
Class 11
MATHS
Find the equations to the straight lines...

Find the equations to the straight lines bisecting the angles between the following pairs of straight lines, placing first the bisector of the angle in which the origin lies.
`12x + 5y-4= 0 and 3x+ 4y+ 7=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equations of the straight lines bisecting the angles between the given pairs of straight lines, we will follow these steps: ### Step 1: Identify the given lines The equations of the lines are: 1. \( L_1: 12x + 5y - 4 = 0 \) 2. \( L_2: 3x + 4y + 7 = 0 \) ### Step 2: Calculate \( L_1(0,0) \) and \( L_2(0,0) \) Evaluate both equations at the origin (0,0): - For \( L_1 \): \[ L_1(0,0) = 12(0) + 5(0) - 4 = -4 \] - For \( L_2 \): \[ L_2(0,0) = 3(0) + 4(0) + 7 = 7 \] ### Step 3: Check the product of \( L_1(0,0) \) and \( L_2(0,0) \) Calculate the product: \[ L_1(0,0) \cdot L_2(0,0) = (-4) \cdot 7 = -28 \] Since the product is less than 0, the origin lies between the two lines. ### Step 4: Use the angle bisector formula The angle bisector formula for two lines \( L_1 \) and \( L_2 \) is given by: \[ \frac{A_1x + B_1y + C_1}{\sqrt{A_1^2 + B_1^2}} = \pm \frac{A_2x + B_2y + C_2}{\sqrt{A_2^2 + B_2^2}} \] Where: - \( A_1 = 12, B_1 = 5, C_1 = -4 \) - \( A_2 = 3, B_2 = 4, C_2 = 7 \) ### Step 5: Calculate the denominators Calculate the square roots: \[ \sqrt{A_1^2 + B_1^2} = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13 \] \[ \sqrt{A_2^2 + B_2^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] ### Step 6: Write the equations for the angle bisectors Using the angle bisector formula: 1. For the bisector where the origin lies: \[ \frac{12x + 5y - 4}{13} = -\frac{3x + 4y + 7}{5} \] Cross-multiplying gives: \[ 5(12x + 5y - 4) = -13(3x + 4y + 7) \] Expanding both sides: \[ 60x + 25y - 20 = -39x - 52y - 91 \] Combining like terms: \[ 99x + 77y + 71 = 0 \] 2. For the bisector where the origin does not lie: \[ \frac{12x + 5y - 4}{13} = \frac{3x + 4y + 7}{5} \] Cross-multiplying gives: \[ 5(12x + 5y - 4) = 13(3x + 4y + 7) \] Expanding both sides: \[ 60x + 25y - 20 = 39x + 52y + 91 \] Combining like terms: \[ 7x - 9y - 37 = 0 \] ### Final Equations The equations of the angle bisectors are: 1. \( 99x + 77y + 71 = 0 \) (bisector where the origin lies) 2. \( 7x - 9y - 37 = 0 \) (bisector where the origin does not lie)
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the lines bisecting the angles between the pair of lines 3x^(2)+xy-2y^(2)=0

The equation to the straight line bisecting the angle between straight lines 12x+5y-2=0 and 3x-4y+7=0is:

Findthe angle between the pair of straight lines x^2 -4y^2+3x - 4 = 0

Find the angles between the pairs of straight line x-y sqrt(3)=5 and sqrt(3)x+y=7

The angle between the pair of straight lines x^(2)+4y^(2)-7xy=0 is

Find the angles between each of the following pairs of straight line: x-4y=3\ a n d\ 6x-y=11.

Find the bisector of acute angle between the lines x+y - 3 = 0 and 7x - y + 5 = 0

Find the angle between the pair of straight lines x^(2) - 3xy +2y^(2) = 0

Find the equations of the bisectors of the angles formed by the following pairs of lines 3x+4y+13=0 and 12x-5y+32=0