Transform to parallel axes through the point `( - 2, 3)` to the equation
`2 x^(2) + 4xy + 5y ^(2) - 4x - 22y + 7 = 0`

Transforming to parallel axes through a point (p,q),the equation 2(x^(2))+3xy+4y^(2)+x+18y+25=0 becomes 2(x^(2))+3xy+4y^(2)=1

Transform the equation x^(2)-3xy+11x-12y+36=0 to parallel axes through the point (-4, 1) becomes ax^(2)+bxy+1=0 then b^(2)-a=

The equation to the pair of lines passing through the point (-2,3) and parallel to the pair of lines x^(2)+4xy+y^(2)=0 is

If the ares are translated to the point (2,-3) then the equation x^(2)+3y^(2)+4x+18y+30=0 transforms to

If the axes are translated to the point (-2,-3) then the equation x^2+3y^2+4x+18y+30=0 transforms to

If the axes are shifted to (-2,-3) and rotated through (pi)/(4) then transformed equation of 2x^(2)+4xy-5y^(2)+20x-22y-14=0 is

In order to eliminate the first degree terms from the equation 2x^(2)+4xy+5y^(2)-4x-22y+7=0, the point to which origin is to be shifted is- -(1)(1,-3)(2)(2,3)(3)(-2,3)(4)(1,3)

What does the equation 2x^(2)+4xy-5y^(2)+20x-22y-14=0 become when referred to the rectangular axes through the point (-2,-3), the new axes being inclined at an angle at 45^(@) with the old axes?