Find the equation to the circle which passes through the origin and cuts orthogonally each of the circles `x^(2) +y^(2) - 6x + 8=0 and x^(2) + y^(2) - 2x - 2y = 7`

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y=7 is

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

The equation of circle which pass through the points (2.0),(0.2) and orthogonal to the circle 2x^(2)+2y^(2)+5x-6y+4=0

Find the centre of the circle that passes through the point (1,0) and cutting the circles x^(2) + y ^(2) -2x + 4y + 1=0 and x ^(2) + y ^(2) + 6x -2y + 1=0 orthogonally is

Find the equation of circle which passes through origin and cuts off intercepts of unit length on lines y^(2)-x^(2)=0