In the diagram shown, the separation between the slit is equal to 3`lambda`, where `lambda` is the wavelength of the light incident on the plane of slits. A thin film of thickness 3`lambda` and refractive index 2 has been placed in front of the upper slit. Assuming D `>``>` `lambda` the distance of the zero order maxima (where phase difference of the zero order) on the screen from O is given most appropriately by :

In Young's double-slit experiment, let A and B be the two slit. A thin film of thickness t and refractive index mu is placed in front of A. Let beta = fringe width. Then the central maxima will shift

In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .

Distance between the slit shown in figure is d = 20 lambda , where lambda is the wavelength of light used. Find the angle theta where a. central maxima (where path difference is zero) is obtained, and b. third-order maxima is obtained.

In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index n_(1) . The wavelength of light in this medium is lambda_(1) . A transparent slab of thickness t and refractive index n_(3) is put in front of one slit. The medium between the screen and the plane of the slits is n_(2) . The phase difference between the light waves reaching point O (symmetrical, relative to the slits) is

The maximum intensity in Young.s double slit experiment is I_0 . Distance between slits is d= 5 lambda , where lambda is the wavelenght of the monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D= 10d .

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is:

The intensity at the maximum in a Young's double slit experiment is I_0 . Distance between two slits is d=5lambda , where lambda is the wavelength of light used in the experiement. What will be the intensity in front of one of the slits on the screen placed at a distance D=10d ?

In figure, if a parallel beam of white light is incident on the plane of the slit, then the distance of the nearest white spot on the screen form O is [assume d lt lt D, lambda lt lt D ]

A monochromatic light of lambda=500 nm is incident on two identical slits separated by a distance of 5xx10^(-4)m . The interference pattern is seen on a screen placed at a distance of 1 m from the plane of slits. A thin glass plate of thickness 1.5xx10^(-6)m and refractive index mu=1.5 is placed between one of the slits and the screen. Find the intensity at the center of the screen if the intensity is I_(0) in the absence of the plate. Also find the lateral shift of the central maxima and number of fringes crossed through center.

A monochromatic light of lambda = 5000 Å is incident on two identical slits separated by a distance of 5 xx 10^(-4) m. The interference pattern is seen on a screen placed at a distance of 1 m from the plane of slits. A thin glass plate of thickness 1.5 xx 10^(-6) m and refractive index mu = 1.5 is placed between one of the slits and the screen . Find the intensity at the center of the screen.