The enthalpy of fusion of ice is `6kJmol^(-1)` The heat capacity of water is `4.2Jg^(-1)c^(-1)` .What is the smallest number of ice cubes at `0^(@)C` ,each containing one mole of water that are needed to cool

Chemical reactions are invariably associated with the transfter of energy either in the form of heat or light. In the laboratory, heat changes in physical and chemical processes are measured with an instrument called calorimeter. Heat change in the process is calculated as {:(q = ms DeltaT,,s ="Specific heat"),(=cDeltaT,,c ="Heat capacity"):} Heat of reaction at constant volume is measured using bomb calorimeter. q_(V) = DeltaU = Internal energy change Heat of reaction at constant pressure is measured using simple or water calorimeter. q_(p) = DeltaH q_(p) = q_(V) +P DeltaV DeltaH = DeltaU +DeltanRT The enthalpy of fusion of ice is 6.02 kJ mol^(-1) . The heat capacity of water is 4.18 J g^(-1)C^(-1) . What is the smallest number of ice cubes at 0^(@)C , each containing one molw of water, the are needed to cool 500g of liquid water from 20^(@)C to 0^(@)C ?

The heat capacity of liquid water is 75.6 J/mol K, while the enthalpy of fusion of ice is 6.0 kJ/mol. What is the smallest number of ice cubes at 0^(@)C , each containing 9.0g of water, needed to cool 500g of liquid water from 20^(@)C " to " 0^(@0C ?

Latent heat of fusion of ice is 0.333 kJ g^(-1) . The increase in entropy when 1 mole water melts at 0^(@)C will be

The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is ?

The enthalpy of fusion of water is 1.435kcal//mol .The molar entropy change for the melting of ice at 0^(@)C is

In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34^@ C to its freezing temperature. The specific heat capacity of water is 4.2 J g^(-1) K^(-1) . Calculate the specific latent heat of ice. State one important assumption made in the above calculation.

10 gram of water at 45^(@)C is added to 5 gram of ice at -30^(@)C . Find the final temperature of the mixture. Specific heat of ice is 0.55 cal g^(-1)""^(@)C^(-1) and that of water is 1.0 cal g^(-1)""^(@)C^(-1) latent heat of fusion of ice is 80 cal g^(-1) ? (ii) To rise the temperature of 100 gram of water from 24^(@) to 90^(@)C by steam at 100^(@)C . Calculate the amount of steam required. Specific heat of water is 1.0 cal g^(-1)""^(@)C^(-1) . Latent heat of steam is 540 Cal kg^(-1) .

A refrigerator converts 100 g of water at 20^@ C to ice at - 10^@ C in 73.5 min. Calculate the average rate of heat extraction in watt. The specific heat capacity of water is 4.2 J g^(-1) K^(-1) , specific latent heat of ice is 336 J g^(-1) and the specific heat capacity of ice is 2.1 J g^(-1) K^(-1)

Equal masses of ice (at 0^@C) and water are in contact. Find the temperature of water needed to just melt the complete ice.

Calculate the heat required to convert 3 kg of ice at -12^(@)C kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given, specific heat capacity of ice = 2100 J kg^(-1) K^(-1) specific heat capicity of water = 4186 J kg^(-1)K^(-1) Latent heat of fusion of ice = 3.35 xx 10^(5) J kg^(-1) and latent heat of steam = 2.256 xx 10^(6) J kg^(-1) .