.Standing wave produced in a metal rod of length 1cm is represented by the equation y=`10^(-6)`sin`(`pi`x/(2))`sin200 `pi` t.The maximum teusil stress at the mid - point of the rod is (y=`10^(12)`N/`m^(2)`)

The transverse wave represented by the equation y = 4 "sin"((pi)/(6)) "sin"(3x - 15 t) has

A wave is represented by the equetion y=7 sin(7pi t-0.04pix+(pi)/(3)) x is in metres and t is in seconds. The speed of the wave is

A wave is represented by the equetion y=7 sin(7pi t-0.04pix+(pi)/(3)) x is in metres and t is in seconds. The speed of the wave is

A wave is represented by the equation y= A sin ( 10 pi x + 15 pi t + (pi)/(6)) wher x is in metre and t in second. The expression represents

A wave is represented by the equation y=0.5 sin (10 t-x)m . It is a travelling wave propagating along the + x direction with velocity

A wave is represented by the equation : y = A sin(10 pi x + 15 pi t + pi//3) where, x is in metre and t is in second. The expression represents.

The equation of a stationary wave in a metal rod is given by y=0.92 sin.(pix)/(3)sin1000t , where x is in cm and t is in second. The maximum tensile stress at a point x = 1 cm is (npi)/(3)xx10^(8)" dyne cm"^(-2) . What is the value of n? [Young's modulus of the material of rod is =8xx10^(11)" dyne cm"^(-2) ]

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is

The equation of a standing wave produced on a string fixed at both ends is y=0.4 "sin"(pix)/(10) cos 600 pi t where y' is measured in om 10 What could be the smallest length of string?

If two SHMs are represented by equations y_(1) = 5 sin (2pi t + pi//6) and y_(2) = 5 [sin (3pi) + sqrt3 cos (3pi t)] . Find the ratio of their amplitudes.