The possible correct set of four quantum numbers for the valence electron of sodium atom `(Z=11)` is
`3,2,1,-(1)/(2)`
`3,1,0,+(1)/(2)`
`3,0,0,+(1)/(2)`
`4,0,0,+(1)/(2)`

Element having (4,0,0+1//2) as a set of four quantum numbers for its valence electron is-

Element having (4,0,0+1//2) as a set of four quantum numbers for its valence electron is-

What are the possible set of quantum number for highest energy electron (in ground state) for chlorine atom. {:(,n,l,m,),((A),2,0,0,),((B),2,1,-2,),((C),3,1,2,),((D),3,1,0,):}

The values of four quantum number of valence electron of an element are n = 4, l = 0, m = 0 and s=+(1)/(2) . The element is:

The quantum numbers for the outer electrons of an atom are given by n = 2, l = 0, m = 0, s = +1//2

Which of the following sets of quantum numbers represent an impossible arrangement :- {:(,n,l,m,m_(s),),((A),3,2,-2,(1)/(2),),((B),4,0,0,(1)/(2),),((C),3,2,-3,(1)/(2),),((D),5,3,0,(1)/(2),):}

Which of the following sets of quantum numbers are impossible for electrons? Explain why in each case. |{:("Set",n,l,m,s),((i),1,0,1,+1/2),((ii),3,0,0,-1/2),((iii),1,2,2,+1/2),((iv),4,3,-3,+1/2),((v),5,2,1,-1/2),((vi),3,2,1,0):}|

By plotting the following points check whether they are collinear or not (i) (1,1), (2,2),(4,4) (ii) (1,0), (-3,0), (0,0) (iii) (2,-2), (0,0), (-3,4)

Explain , giving reason , which of the following sets of quantum number are not possible {:(a,n= 0 ,l = 0, m_(1) = 0, m_(s) = +1//2),(b,n= 1 ,l = 0, m_(1) = 0, m_(s) = -1//2),(c,n= 1 ,l = 1, m_(1) = 0, m_(s) = +1//2),(d,n= 2 ,l = 1, m_(1) = 0, m_(s) = -1//2),(e,n= 3 ,l = 3, m_(1) = -3, m_(s) = +1//2),(f,n= 3 ,l = 1, m_(1) = 0, m_(s) = +1//2):}

In the structure of diamond, carbon atoms appear at a. 0, 0, 0 , and (1)/(2), (1)/(2), (1)/(2) b. (1)/(4), (1)/(4), (1)/4 , and (1)/(2), (1)/(2), (1)/(2) c. 0, 0, 0 , and (1)/(4), (1)/(4), (1)/(4) d. 0, 0, 0 , and (3)/(4), (3)/(4), (3)/(4)