When `2`moles of `Na_(2)CO_(3)` reacts with `6`moles of `HCl`, the volume of `CO_(2)` gas liberated at S.T.P will be

One mole of CO_(2) contains:

When 15 g of a mixture of NaCl and Na_(2)CO_(3) is heated with dilute HCl, 2.5 g of CO_(3) is evolved at NTP. Calculate percentage composition of the original mixture.

Calculate volume occupied by 2.2 g of CO_(2) at S.T.P.

Calculate the mass of 2.8 litres of CO_(2) at S.T.P.

The gas evolved on heating Na_(2)CO_(3) is

90 g of acetic acid react with excess of NaHCO_(3) then what volume of CO_(2) will produce at S.T.P. Write your answer in terms of nearest integer.

Calculate the number of mole of Na_(2)S_(2)O_(3) that will react with I_(2) obtained when 1 mole of K_(2)Cr_(2)O_(7) reacts with excess of Kl in acidic medium.

112% labelled oleum is diluted with sufficient water. The solution on mixing with 5.3 gm Na_(2)CO_(3) liberates CO_(2) . The volume of Co_(2) given out at 1 atm at 273 K will be

6 mole of FeC_2 O_4 on treatment with 2 mole of K_2 Cr_2 O_7 in acidic medium evolves x litre of CO_2 gas at STP. The value of x would be:

When 1 L of CO_2 is heated with graphite , the volume of the gases collected is 1.5 L. Calculate the number of moles of CO produced at STP