If there are two children in a family and the probability that there is atleast one girl in the family is p\q,where p.q are co-prime no,find p+q:

There are two children in a family. Find the probability that at most one boy is there in the family.

Two smallest squares are chose at random on a chess board and p/q is the probability that they have exactly one corner in common ( p and q are co-prime) then q-20p=

Assume that in family ,each child is equally likely to be a boy or a girl . A family with three children is chosen at random . The probalility that the eldest child is girl given that the family has atleast one girl is

India and Australia play a series of 7 one-day matches. Each team has equal probability of winning a match. No match ends in a draw. If the probability that India wins atleast three consecutive matches can be expressed as (p)/(q) where p and q are relatively prime positive integers. Find the unit digit of p.

There are two family each having two children. If there are at least two girls among the children, find the probability that all children are girls

Contrapositive of "if p· then q" is (where p and q are statement)

Three different numbers are selected at random from the set A={1,2,3,……..,10} . Then the probability that the product of two numbers equal to the third number is (p)/(q) , where p and q are relatively prime positive integers then the value of (p+q) is :

Assume that for every person the probability that he has exactly one child, exactly 2 children and exactly 3 children are (1)/(4), (1)/(2) and (1)/(4) respectively . The probability that a person will have 4 grand children can be expressed as (p)/(q) where p and q are relatively prime positive integers. Find the value of 5p-q .

If the distance from the point P(1, 1, 1) to the line passing through the points Q(0, 6, 8) andR(-1, 4, 7) is expressed in the form sqrt((p)/(q)) , where p and q are co-prime, then the value of ((q+p)(p+q-1))/(2) is equal to

"If p then q" is same as (where p and q are statement)