Find weight in gram of glucose (`Mw`=180)that should be dissolved in 100 g water in order to produce a solution with a difference of `105^(@)`C between its boiling point and freezing point temperatures (Take `Kf`=2 K-Kg/mole, `Kb`=0.5K-Kg/mole)

The amount (in grams) of sucrose (mol.wt. = 342g) that should be dissolved in 100 g water in order to produce a solution with a 105.0^@C difference between the boiling point and freezing point is (Given that k_f=1.86Kkgmol^(-1) and k_b=0.52Kkgmol^(-1)" for water") Report your answer by rounding it up to to the nearest whole number.

How many moles of sucrose should be dissolved in 500gms of water so as to get a solution which has a difference of 104^(@)C between boiling point and freezing point. (K_(f)=1.86 K Kg "mol"^(-1).K_(b)=0.52K Kg "mol"^(-1))

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))

What weight of glycerol should be added to 600 g of water in order to lower its freezing point by 10^@ C ? (K_f=1.86^@ C m^(-1))

When 1 mole of a solute is dissolved in 1 kg of H_(2)O , boiling point of solution was found to be 100.5^(@) C. K_(b) for H_(2)O is :

0.1 mole of sugar is dissolved in 250 g of water. The freezing point of the solution is [K_(f) "for" H_(2)O = 1.86^(@)C "molal"^(-1)]

When 0.6g of urea dissolved in 100g of water, the water will boil at (K_(b) for water = 0.52kJ. mol^(-1) and normal boiling point of water =100^(@)C) :

Boiling point of 100 g water containing 12 g of glucose dissolved in 100.34^@C . What is K_b of water ?

The weight of ethyl alcohol which must be added to 1.0 L of water so that the solution will freeze at 14^@F is (K_f of water = 1.86 K kg mol^(-1) )

18 g of glucose (C_(6)H_(12)O_(6)) is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (at 1 atm) ? K_(b) for water is 0.52 K kg mol^(-1) .