Std 10 gujarati ch 16 gati bhang swadhyay solution , dhoran 10 gujarati ch 16 swadhyay solution

Calculate the pH at the equivalence point when a solution of 0.1 M CH_3COOH is titrated with a solution of 0.1 M NaOH. K_a(CH_3COOH)= 1.8 xx 10^(-5)

20 mol of M//10 CH_(3)COOH solution is titrated with M//10 NaOH solution. After addition of 16 mL solution of NaOH . What is the pH of the solution (pK_(a) = 4.74)

Ionisation constant of CH_(3)COOH is 1.7 xx 10^(-5) and concentration fo H^(+) in certain acetic acid solution is 3.4 xx 10^(-4) M . The concentration of acetic acid solution is

1 litre of 1M CH_(3)COOH (very weak acid) taken in a container initially. Now this solution is diluted upto volumen V (litre) so that pH of the resulting solution becomes twice the original value. (K_(a) (CH_(3)COOH) = 10^(-6)) . Now equal volume of 0.5 xx 10^(-6)M NaOH solution is added to this resulting solution, so that a buffer solution is obtained. Find pH of final solution (log 3 = 0.477 ).

0.5 moles of HCI and 0.5 moles of CH_(3)COONa are disolved in water and the solution is made upto 500 ml. The H ^+ of the resulting solution will be: (K_(a) (CH_(3)COOH) = 1.6 xx 10^(-5))

An aqueous solution of CH_3 COONa is

a. Write an equilibriu equation for a solution containing CH_(3)COOH and CH_(3)COONa . What effect does CH_(3)COONa have on a solution of CH_(3)COOH ? b. What reagents should be added to a solution to increase i. [CH_(3)COO^(Theta)] ii. [overset(o+)NH_(4)]

0.1 M CH_(3) COOH solution is 1.0% ionized. In another diluted solution acetic acid is 10% ionised. In other solution concentration of acetic acid is