The number of electrons gained by `KMnO_4` in acidic medium is

In the titration of FeSO_(4) against KMnO_(4) in acidic medium, one mole of KMnO_(4) reacts with x moles of FeSO_(4) . The value of x is

0.1 M solution of KMnO_(4) (in acidic medium) may oxidies

A : H_2O liberate O_2 an reaction with KMnO_4 in acidic medium. R : KMnO_4 oxidises H_2O_2" to " O_2 .

STATEMENT-1: The equivalent mass of of KMnO_(4) in acidic medium is (M)/(5) where M=molecular mass of KMnO_(4) STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

n-Factor of KMnO_(4) in neutral medium is

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO_(2) is

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO_(2) is

Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

How many moles of FeC_2O_4 are required to reduce 2 " mol of " KMnO_4 in acidic medium?

The molarity (m) of KMnO_(4) in the acidic medium is (densityh of KMnO_(4) solution =1.58gmL^(-1)Mw(KMnO_(4))=158gmol^(-1))