`log_2 3+log_2 2-log_2 6-log_2 8`

If log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0 , then the value of (x+y) is

Solve the following equation for x: 9^(log_3(log_2x))=log_2 x- (log_2 x)^2+1

let y=sqrt(log_2(3)log_2(12)log_2(48)log_2(192)+16)-log_2(12)log_2(48)+10 find y

Comprehension 2 In comparison of two numbers, logarithm of smaller number is smaller, if base of the logarithm is greater than one. Logarithm of smaller number is larger, if base of logarithm is in between zero and one. For example log_2 4 is smaller than (log)_2 8\ a n d(log)_(1/2)4 is larger than (log)_(1/2)8. Identify the correct order: (log)_2 6 (log)_3 8> log_3 6>(log)_4 6 (log)_3 8>(log)_2 6> log_3 6>(log)_4 6 (log)_2 8<(log)_4 6

The solution set of the system of equations log_12 x(1/(log_x 2)+log_2 y)=log_2 x and log_2 x.(log_3(x+y))=3 log_3 x is : (i) x=6, y=2 (ii) x=4, y=3 (iii) x=2, y=6 (iv) x=3, y=4

If log_2 (log_8x)=log_8(log_2x), find the value of (log_2x)^2.

log_3 2, log_6 2, log_12 2 are in

What is the real value of x in the eqaution, log_2 80- log_2 5 = log_3 x ?

if x >0 , and log_2 x + log_2 (x^(1/2)) + log_2 (x^(1/4))+ ------------ = 4 then x equals :

Find the value of 2log2/5 +3 log25/8 -log 625/128