The equivalent mass of `H_3PO_4` in the reaction given below is
`H_3PO_4 +NaOH to NaH_2PO_4 + H_2O`

Shape of H_3PO_4 is

Find the equivalent mass of H_3PO_4 in the following reaction : Ca(OH)_(2) + H_(3)PO_(4) to CaHPO_(4) + 2H_(2)O

Find out the equivalent weight of H_(3) PO_(4) in the reaction: Ca(OH)_(2) + H_(3) PO_(4) rarr CaHPO_(4) + 2 H_(2) O

Equivalent mass of H_3PO_2 when it disproportionate into PH_3 and H_3PO_3 is (mol. wt. of H_3PO_2 = M ) :

Calculate equivalent weight of H_(3)PO_(4) and Ca(OH)_(2) on the basis of given reaction. H_(3)PO_(4)+ NaOH to NaH_(2)PO_(4)+ H_(2)O Ca(OH)_(2)+ HCL to Ca(OH)CL+ H_(2)O

In the given reaction: P_4 + NaOH + H_2O rarr PH_3 + NaH_2PO_2

What is the n-factor for H_(3)PO_(4) in the reaction 2NaOH+H_(3)PO_(4)rarr Na_(2)HPO_(4)+2H_(2)O ?

One mole of H_3PO_3 on reaction with excess of NaOH gives :

Equivalent weight of H_(3)PO_(4) in each of the reaction will be respectively - H_(3)+OH^(-)rarrH_(2)PO_(4)+H_(2) H_(3)PO_(4)+2OH^(-)rarrHPO_(4)^(2-)+2H_(2)O H_(3)PO_(4)+2OH^(-)rarrPO_(4)^(3-)+3H_(2)O

Draw the strucutres of the following H_3PO_4