If focal length of a plano-covex lens is 20 cm and `mu` =1.5 , then the radius of curvature of the lens is

The focal length of equiconvex lens of retractive index, mu=1.5 and radius of curvature, R is

Radius of curvature of first surface of double convex lens is three times that of the other. If focal length of the lens is 30 cm and refractive index of the lens is 3/2, then radius of curvature of the first surface is

Assertion : The focal length of an equiconvex lens placed in air is equal to radius of curvature of either face. Reason : For an equiconvex lens radius of curvature of both the faces is same.

The convex surface of a plano-convex lens is silvered and the radius of curvature of this surface is R. Find the focal length of the system:

The plane surface of a plano-convex lens of refracting index 1.5, is silvered. The radius of curvature of curved surface is R. Find the focal length of the mirror thus formed.

The radius of curvature of the curved surface of a plano-convex lens is 20 cm . If the refractive index of the material of the lens be 1.5 , it will

What is the refractive index of material of a plano-convex lens , if the radius of curvature of the convex surface is 10 cm and focal length of the lens is 30 cm ?

The refractive index of a material of a plano-concave lens is 5/3 , the radius of curvature is 0.3 m. The focal length of the lens in air is

What is the approximate radius of the central bright differaction spot of light of wavelength lambda=0.5 mum , if focal length of the lens is 20 cm and radius of aperture of the lens is 5 cm ?

Find the refractive index of the material of a plano-convex lens, if the radius of curvature of the convex surface is 20 cm and focal length of the lens is 60 cm?