A particle of mass m is performing linear simple harmonic motion Its equilibrium is at x = 0, force constant is K and amplitude of SHM is A. The maximum power supplied by the restoring force to the particle during SHM will be

A mass M is performing linear simple harmonic motion. Then correct graph for acceleration a and corresponding linear velocity v is

A particle starts performing simple harmonic motion. Its amplitude is A . At one time its speed is half that of the maximum speed. At this moment the displacement is

A particle of mass m performs SHM along a straight line with frequency f and amplitude A:-

A particle is executing a simple harmonic motion. Its maximum acceleration is alpha and maximum velocity is beta . Then, its time period of vibration will be

A particle of mass 200 g executes a simple harmonic motion. The restoring force is provided by a spring of spring constant 80 N//m . Find the time period.

A 0.5 kg body performs simple harmonic motion with a frequency of 2 Hz and an amplitude of 8 mm . Find the maximum velocity of the body, its maximum acceleration and the maximum restoring force to which the body is subjected.

A particle of mass 10g is undergoing SHM of amplitude 10cm and period 0.1s. The maximum value of force on particle is about

A particle executing simple harmonic motion has amplitude of 1 m and time period 2 s . At t = 0 , net force on the particle is zero. Find the equation of displacement of the particle.

A student says that he had applied a force F=-ksqrt(x) on a particle and the particle performs in simple harmonic motion. He refuses to tell whether k is a constant or not. Assume that he has worked only with positive x and no other force acted on the particle.

A particle performing simple harmonic motion undergoes unitial displacement of (A)/(2) (where A is the amplitude of simple harmonic motion) in 1 s. At t=0 , the particle may be at he extreme position or mean position the time period of the simple harmonic motion can be