Find the value of `sqrt(2sqrt(2sqrt2))=?`

Find the value of x in sqrt(x+2sqrt(x+2sqrt(x+2sqrt(3x))))...=x.

4.Find the value of "1/(sqrt5+sqrt2)

Find the value of sqrt((x+2sqrt((x-1)))]+sqrt((x-2sqrt((x-1)))] =

Find the Value of \ sqrt(2+sqrt(2+2cos4theta))

The value of x=sqrt(2+sqrt(2+sqrt(2+...))) is (a) -1 (b) 1 (c) 2 (d) 3

If sqrt(2)=1.414 , then find the value of (1)/(2+sqrt(2))

If a =( 4sqrt(6))/(sqrt(2)+sqrt(3)) then the value of (a+2sqrt(2))/(a-2sqrt(2))+(a+2sqrt(3))/(a-2sqrt(3))

If sqrt(2)=1*4 and sqrt(3)=1*7 , find the value of 1/(sqrt(3)-sqrt(2)) , correct to one place of decimal.

The value of sqrt(2-1)/sqrt(2)+3-2sqrt(2)/(4)+(5sqrt2-7/6)sqrt(2)+17-12sqrt(2)/(16)+..+++..+ add.infty is

Using binomial theorem, write the value of (a+b)^(6) + (a-b)^(6) and hence find the value of ( sqrt(3) + sqrt(2) )^(6) + ( sqrt(3) - sqrt(2) )^(6) .