Find the value of `sqrt(2sqrt(3sqrt2))`

Using binomial theorem, write the value of (a+b)^(6) + (a-b)^(6) and hence find the value of ( sqrt(3) + sqrt(2) )^(6) + ( sqrt(3) - sqrt(2) )^(6) .

Find the value of sqrt((x+2sqrt((x-1)))]+sqrt((x-2sqrt((x-1)))] =

If sqrt(2)=1*4 and sqrt(3)=1*7 , find the value of 1/(sqrt(3)-sqrt(2)) , correct to one place of decimal.

Find the value of 6/(sqrt(5)-\ sqrt(3)) , it being given that sqrt(3)=1. 732\ \ a n d\ \ sqrt(5)=2. 236

Find the value of x in sqrt(x+2sqrt(x+2sqrt(x+2sqrt(3x))))...=x.

Rationalize the denominator and simplify to find the value of 4/(sqrt(5)+sqrt(3)) , given that sqrt(5)=2.236 and sqrt(3)=1.732

If sqrt(2)=1.414 , then find the value of (1)/(2+sqrt(2))

If sqrt(3) = 1.73 find the value of : (2+sqrt(3))/(2-sqrt(3))+(2-sqrt(3))/(2+sqrt(3))+(sqrt(3)-1)/(sqrt(3)+1)-(sqrt(3)+1)/(sqrt(3)-1) .

if sqrt2=1.414and sqrt3=1.732 then find the value of 4/(3sqrt3-2sqrt2)+3/(3sqrt3+2sqrt2)

Find the value of: 1/(1+sqrt2)+1/(sqrt2+sqrt3)+1/(sqrt3+sqrt4)+...1/(sqrt99+sqrt100)