No.of atoms in 4.25 g. of `NH_3` is approx :- (1) `1times` `10^23` (2) `1.5 times` `10^23` (3) `2 times` `10^23` (4) `6 times` `10^23`

Number of electrons present in 3.6 mg of NH_(4)^(+) are : (N_(A) = 6 xx 10^(23))

The number of electron in 3.1 mg NO_(3)^(-) is ( N_(A) = 6 xx 10^(23) )

The number of atoms in 0.1 mole of a triatomic gas is (N_(A) = 6.02 xx 10^(23) "mol"^(-1))

Number of electrons in 36mg of ._8^(18)O^(-2) ions are : (Take N_(A) = 6 xx 10^(23))

The number of atoms in 0.1 mol of a tetraatomic gas is ( N_(A) = 6.02 xx 10^(23) mol^(-1) )

Find mass of 12.046 xx 10^(23) atoms .^(12)C_(6) sample ? .

The number of F^- ions in 2.1 g AlF_3 is (N_A=6xx10^23)

The total number of protons in 10 g of calcium carbonate is (N_(0) = 6.023 xx 10^(23)) :-

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23)) , mass of e^(-) = 9.1 xx 10^(-31)Kg

Express the following numbers in usual form. (i) 3.02 xx 10^-6 (ii) 4.5 xx 10^4 (iii) 3 xx 10^(-8) (iv) 1.0001 xx 10^9 (v) 5.8 xx 10^12 (vi) 3.61492 xx 10^6