I=int(0)^(2)(x^2-4)dx-int(2)^3(x^2-4)dx...

`I=int_(0)^(2)(x^2-4)dx-int_(2)^3(x^2-4)dx`

I=int(0)^(2)(x^2-4)dx-int(2)^3(x^2-4)dx
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int(0)^(a)(x^(4))/((a^(2)+x^(2))^(4))dx
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int(0)^(a)(x^(4))/((a^(2)+x^(2))^(4))dx
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Evaluate : int(0)^(4) x(4-x)^(3//2)dx
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int(3)^(4)(dx)/((x^(2)-4))
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int(0)^(a)(x^(4)dx)/((a^(2)+x^(2))^(4)) का मान है -
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If I(1)=int(0)^(1) 2^(x^(2)) dx, I(2)=int(0)^(1) 2^(x^(3)) dx, I(3)=in...
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If I = int(0)^(pi//4) sin^(2) x" "dx and J = int(0)^(pi//4)cos^(2)x" "...
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I=int(0)^(4)(x^(2)+2x+4)dx
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