`y=(x^2+1)(x+5+1/x)` , then `dy/dx` is :
(A)`2x(x+5+1/x)+(x^2+1)(1-1/x^2)`
(B) `2x(x+5+1/x)-(x^2+1)(1-1/x^2)`
(C) `2x+1-1/x^2`
(D)`0`

(x-1) / (2x + 1) + (2x + 1) / (x-1) = (5) / (2), x! =-(1) / (2), 1

(2x + 1) / (x) + (4x) / (2x + 1) = 5

The factor of x^8 + x^4 +1 are (A) (x^4 + 1 - x^2), (x^2 +1 +x), (x^2 + 1 - x ) (B) x^4 + 1 -x^2 , (x^2 - 1 + x), (x^2 +1 + x) (C ) (x^4 - 1 + x^2, (x^2 - 1 + x), (x^2 + 1 + x) (D) (x^4 -1 + x^2), (x^2 + 1 - x), (x^2 + 1 +x)

(dy)/(dx)+(x)/(1+x^(2))y=(1)/(2x(1+x^(2)))

If y=cos^(-1)sqrt((sqrt(1+x^(2))+1)/(2sqrt(1+x^(2)))),then(dy)/(dx) is equal to (a) (1)/(2(1+x^(2))),x in R(b)(1)/(2(1+x^(2))),x>0(c)(-1)/(2(1+x^(2))),x<0 (d) (1)/(2(1+x^(2))),x<0

If y=(1+(1)/(x^(2)))/(1-(1)/(x^(2)))backslash then (dy)/(dx)=-(4x)/((x^(2)-1)^(2))b-(4x)/(x^(2)-1) c.(1-x^(2))/(4x)d*(4x)/(x^(2)-1)

If (x+(1)/(x))=2, then (x-(1)/(x)) is equal to (a) 0 (b) 1 (c) 2 (d) 5

If y=tan^(-1)sqrt((x+1)/(x-1)), then (dy)/(dx) is (-1)/(2|x|sqrt(x^(2)-1)) (b) (-1)/(2x sqrt(x^(2)-1))(1)/(2x sqrt(x^(2)-1))( d) none of these

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)