`log_4(x+3)-log_4(x-1)=2-log_4 8` find x=?

Solve log_4 (8)+log_4 (x+3)-log_4 (x-1)=2

Solve (log)_4 8+(log)_4(x+3)-(log)_4(x-1)=2.

Solve log_4(log_3x)-log_(1//4)(log_(1//3)y)=0 and x^2+y^2=17/4 .

If log_2 (log_8x)=log_8(log_2x), find the value of (log_2x)^2.

The sum of all the roots of the equation log_(2)(x-1)+log_(2)(x+2)-log_(2)(3x-1)=log_(2)4

Solve log_(4)(x-1)= log_(2) (x-3) .

If 6/5 a^A-3^B=9^C where A=log_a x.log_(10) alog_a 5,B=log_(10) (x/10) and C=log_(100) x+log_4 2 . Find x

The number of solution of log_4(x-1)=log_2(x-3) is :

Number of solutions of log_4(x-1)=log_2(x-3) is :

Solve the following equations : (i) log_(x)(4x-3)=2 (ii) log_2(x-1)+log_(2)(x-3)=3 (iii) log_(2)(log_(8)(x^(2)-1))=0 (iv) 4^(log_(2)x)-2x-3=0