A ball is thrown with a velocity of u making an angle θ with the horizontal. Its velocity vector will be normal to its initial velocity vector(u) after a time interval of :

A ball is thrown with velocity 8 ms^(-1) making an angle 60° with the horizontal. Its velocity will be perpendicular to the direction of initial velocity of projection after a time of (g =10ms^(-2) )

A body is thrown with a velocity of 9.8 m/s making an angle of 30^(@) with the horizontal. It will hit the ground after a time

A particle is projected with velocity u at angle theta with horizontal. Find the time when velocity vector is perpendicular to initial velocity vector.

A particle is projected with velocity u at angle theta with horizontal. Find the time when velocity vector is perpendicular to initial velocity vector.

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A particle is projected with a velocity u making an angle theta with the horizontal. The instantaneous power of the gravitational force

A projectile is thrown with initial velocity u_(0) and angle 30^(@) with the horizontal. If it remains in the air for 1s. What was its initial velocity ?

A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is

A body is projected with an initial Velocity 20 m/s at 60° to the horizontal. Its velocity after 1 sec is

A projectile is thrown with a velocity of 20 m//s, at an angle of 60^(@) with the horizontal. After how much time the velocity vector will make an angle of 45^(@) with the horizontal (in upward direction) is (take g= 10m//s^(2))-