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If vec(a) = 2 hat(i) + 4hat(j) = hat(k) ...

If `vec(a) = 2 hat(i) + 4hat(j) = hat(k) ` and `vec(b) = 3 hat(i) - 2hat(j) - lambda hat(k)` such that they are perpendicular to each other , then the value of `lambda ` will be :

A

2

B

`-2`

C

3

D

`-3`

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