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Consider the two vectors veca = 3hati + ...

Consider the two vectors `veca = 3hati + 2hatj + 4hatk` and `hatb = hati - 3hatj + hatk`
The area of the parallelogram formed by `veca and vecb` as its diagonals will be equal to :

A

`1/2 sqrt(318)`

B

`2sqrt(318)`

C

`1/2 sqrt(308)`

D

`2sqrt(308)`

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