Complete the following reaction:
`XeF_6+KF rarr`

Options

A. `K+XeF_7`
B. `[XeF_3]^+[KF_6]^(-)`
C. `KXeF_6`
D. `K^+[XeF_7]^(-)`

Answer

To complete the reaction between \( \text{XeF}_6 \) and \( \text{KF} \), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- \( \text{XeF}_6 \) (Xenon hexafluoride)
- \( \text{KF} \) (Potassium fluoride)

### Step 2: Understand the Nature of the Reactants
- \( \text{XeF}_6 \) is a covalent compound where xenon is in a +6 oxidation state.
- \( \text{KF} \) is an ionic compound consisting of \( \text{K}^+ \) (potassium ion) and \( \text{F}^- \) (fluoride ion).

### Step 3: Analyze the Interaction
Xenon can expand its octet due to the presence of empty d orbitals. In this reaction, the fluoride ions from \( \text{KF} \) can interact with \( \text{XeF}_6 \).

### Step 4: Formation of the Product
When \( \text{XeF}_6 \) reacts with \( \text{KF} \), the fluoride ions from \( \text{KF} \) will coordinate with the xenon, leading to the formation of the complex ion \( \text{XeF}_7^- \) and the potassium ion \( \text{K}^+ \).

### Step 5: Write the Balanced Reaction
The balanced chemical equation for the reaction is:
\[ \text{XeF}_6 + \text{KF} \rightarrow \text{XeF}_7^- + \text{K}^+ \]

### Final Answer
The complete reaction is:
\[ \text{XeF}_6 + \text{KF} \rightarrow \text{XeF}_7^- + \text{K}^+ \]

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