Glucose reacts with HI to form:

Options

A. n-Hexane
B. Gluconic acid
C. Fructose
D. None of these

Answer

To solve the problem of what glucose (C₆H₁₂O₆) forms when it reacts with hydroiodic acid (HI), we can follow these steps:

### Step 1: Understand the Reactants
Glucose is a simple sugar with the formula C₆H₁₂O₆. Hydroiodic acid (HI) is a strong acid that can act as a reducing agent.

**Hint:** Identify the chemical formulas of the reactants involved in the reaction.

### Step 2: Recognize the Reaction Type
When glucose reacts with HI, it undergoes a reduction reaction. HI can provide hydrogen ions (H⁺) and iodide ions (I⁻), which can lead to the reduction of the aldehyde group in glucose.

**Hint:** Determine the type of reaction taking place and the role of HI in the reaction.

### Step 3: Identify the Products
The reaction of glucose with HI typically leads to the formation of iodine and alkanes. Specifically, glucose can be converted into n-hexane (C₆H₁₄) and iodine (I₂). The reaction can be summarized as follows:

\[ \text{C}_6\text{H}_{12}\text{O}_6 + 6 \text{HI} \rightarrow \text{C}_6\text{H}_{14} + 6 \text{I}_2 + 6 \text{H}_2\text{O} \]

**Hint:** Predict the products based on the reactants and the type of reaction occurring.

### Step 4: Write the Balanced Equation
Ensure that the equation is balanced in terms of the number of atoms for each element on both sides of the equation.

**Hint:** Check that all elements are balanced in the final equation.

### Final Answer
When glucose reacts with hydroiodic acid (HI), it forms n-hexane (C₆H₁₄) and iodine (I₂) along with water (H₂O).

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