A body has a positive charge of `8xx10^(-19)` C. It has :

Options

A. an excess of 5 electrons
B. a deficiency of 5 electrons
C. an excess of 8 electrons
D. a deficiency of 8 electrons

Answer

To solve the problem, we need to determine how many electrons are missing from a body that has a positive charge of \(8 \times 10^{-19}\) coulombs.

### Step-by-Step Solution:

1. **Understand the Charge of an Electron**:
The charge of a single electron is approximately \( -1.6 \times 10^{-19} \) coulombs. Since the body has a positive charge, it indicates a deficiency of electrons.

2. **Calculate the Number of Missing Electrons**:
To find out how many electrons are missing, we can use the formula:
\[ n = \frac{Q}{e} \]
where:
- \( n \) is the number of missing electrons,
- \( Q \) is the positive charge of the body, which is \( 8 \times 10^{-19} \) C,
- \( e \) is the charge of one electron, which is \( 1.6 \times 10^{-19} \) C.

3. **Substituting the Values**:
Substitute the values into the formula:
\[ n = \frac{8 \times 10^{-19}}{1.6 \times 10^{-19}} \]

4. **Perform the Division**:
Now, perform the division:
\[ n = \frac{8}{1.6} = 5 \]

5. **Conclusion**:
Therefore, the body has a deficiency of 5 electrons.

### Final Answer:
The body has a deficiency of **5 electrons**.

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