If a current of 0.5 A flows in a 60 W lamp, then the total charge passing through it in two hours will be :

Options

A. 1800 C
B. 2400 C
C. 3000 C
D. 3600 C

Answer

To solve the problem of finding the total charge passing through a 60 W lamp with a current of 0.5 A in two hours, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time
The relationship between current (I), charge (Q), and time (t) is given by the formula:
\[ I = \frac{Q}{t} \]
From this, we can rearrange the formula to find the total charge:
\[ Q = I \times t \]

### Step 2: Convert time from hours to seconds
The time given in the problem is 2 hours. We need to convert this into seconds because the current is in Amperes (Coulombs per second).
1 hour = 3600 seconds, so:
\[ t = 2 \text{ hours} = 2 \times 3600 \text{ seconds} = 7200 \text{ seconds} \]

### Step 3: Substitute the values into the formula
Now that we have the current (I = 0.5 A) and the time (t = 7200 seconds), we can substitute these values into the formula for charge:
\[ Q = I \times t \]
\[ Q = 0.5 \, \text{A} \times 7200 \, \text{s} \]

### Step 4: Calculate the total charge
Now we perform the multiplication:
\[ Q = 0.5 \times 7200 = 3600 \, \text{Coulombs} \]

### Final Answer
The total charge passing through the lamp in two hours is:
\[ Q = 3600 \, \text{C} \]

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