As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle . The potential at the vertex A is :

Options

A. `1/(4pi epsilon_0) * (2q)/(sqrt(a^2))`
B. `1/(4pi epsilon_0) * q/(sqrt(a^2))`
C. `1/(4pi epsilon_0) * ((-q))/(sqrt(a^2))`
D. zero

Answer

D