Read the following paragraph and answer the question :The figure shows a series LCR circuit :For such a circuit, the impedance `Z=sqrt(R^2+(X_L-X_C)^2)` , is given by where `X_L`, and `X_C` are inductive and capacitive resistances respectively. As the frequency of a.c. is increased, at a particular frequency. `X_L` become, equal to `X_C`. For that frequency maximum current occurs. This is because impedance becomes equal is its least value R. Current through the circuit `I= V/R`. The circuit behaves like a pure resistive circuit and current and voltage will be in phase. This is called resonance. Frequency of a.c. at which resonance occurs is called resonant frequency. If frequency is less than the resonant frequency, then the capacitive reactance will be more. The circuit will be capacitive in nature and current leads voltage. On the other hand, if frequency is more than the resonant frequency inductive reactance will be more. Circuit is inductive in nature and current lags the voltage. An LCR circuit with a resistance `50 Omega` has a resonant angular frequency `2 xx 10^3` rad/s. At resonance, the voltage across the resistance and inductance are 25 V and 20 V respectively. Then: Which of the following angular frequency of a.c. will see the circuit as inductive in nature ?