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Relative permittivity of water is 81.If ...

Relative permittivity of water is 81.If `epsilon_w` and `epsilon_0` are permittivity 's of water and vacuum respectively, then:

A

`epsilon_0=9epsilon_w`

B

`epsilon_0=81epsilon_w`

C

`epsilon_w=9epsilon_0`

D

`epsilon_w=81epsilon_0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the permittivity of water (\( \epsilon_w \)) and the permittivity of vacuum (\( \epsilon_0 \)), given that the relative permittivity of water (\( \epsilon_r \)) is 81. ### Step-by-Step Solution: 1. **Understand the Definition of Relative Permittivity**: The relative permittivity (\( \epsilon_r \)) of a material is defined as the ratio of the permittivity of that material (\( \epsilon_w \)) to the permittivity of vacuum (\( \epsilon_0 \)). \[ \epsilon_r = \frac{\epsilon_w}{\epsilon_0} \] 2. **Substitute the Given Value**: We know from the problem that the relative permittivity of water is 81. Therefore, we can write: \[ 81 = \frac{\epsilon_w}{\epsilon_0} \] 3. **Rearranging the Equation**: To find the relationship between \( \epsilon_w \) and \( \epsilon_0 \), we can rearrange the equation: \[ \epsilon_w = 81 \cdot \epsilon_0 \] 4. **Conclude the Result**: From the rearranged equation, we find that the permittivity of water is: \[ \epsilon_w = 81 \epsilon_0 \] ### Final Answer: Thus, the correct relationship is: \[ \epsilon_w = 81 \epsilon_0 \] This corresponds to option 4. ---
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