The Earth's magnetic field at some place on magnetic equator of Earth is `0.5 xx 10^(-4)T.` Consider the radius of Earth at that place as 6400 km. Then, magnetic dipole moment of the Earth is ....`Am^(2)` `(mu=4pixx 10^(-7)TmA^(-1))`

Options

A. `1.05 xx 10^23`
B. `1.15 xx 10^23`
C. `1.31 xx 10^23`
D. `1.62 xx 10^23`

Answer

C