Home
Class 12
MATHS
The domain of R is: R={x,y):x+2y=8 , x,...

The domain of R is:
`R={x,y):x+2y=8 , x,y in N}`

A

{2,4,8}

B

{2,4,6,8}

C

{2,4,6}

D

{1,2,3,4}

Text Solution

AI Generated Solution

The correct Answer is:
To find the domain \( R \) defined by the equation \( x + 2y = 8 \) where \( x \) and \( y \) are natural numbers, we will follow these steps: ### Step 1: Understand the equation We start with the equation given in the problem: \[ x + 2y = 8 \] This equation relates \( x \) and \( y \). ### Step 2: Express \( y \) in terms of \( x \) Rearranging the equation to solve for \( y \): \[ 2y = 8 - x \] \[ y = \frac{8 - x}{2} \] ### Step 3: Determine the values of \( x \) Since \( x \) and \( y \) must be natural numbers (i.e., positive integers), we need to find values of \( x \) such that \( y \) remains a natural number. ### Step 4: Find possible values of \( x \) We will substitute natural numbers for \( x \) and check if \( y \) is also a natural number: - If \( x = 1 \): \[ y = \frac{8 - 1}{2} = \frac{7}{2} = 3.5 \quad (\text{not a natural number}) \] - If \( x = 2 \): \[ y = \frac{8 - 2}{2} = \frac{6}{2} = 3 \quad (\text{natural number}) \] - If \( x = 3 \): \[ y = \frac{8 - 3}{2} = \frac{5}{2} = 2.5 \quad (\text{not a natural number}) \] - If \( x = 4 \): \[ y = \frac{8 - 4}{2} = \frac{4}{2} = 2 \quad (\text{natural number}) \] - If \( x = 5 \): \[ y = \frac{8 - 5}{2} = \frac{3}{2} = 1.5 \quad (\text{not a natural number}) \] - If \( x = 6 \): \[ y = \frac{8 - 6}{2} = \frac{2}{2} = 1 \quad (\text{natural number}) \] - If \( x = 7 \): \[ y = \frac{8 - 7}{2} = \frac{1}{2} = 0.5 \quad (\text{not a natural number}) \] - If \( x = 8 \): \[ y = \frac{8 - 8}{2} = \frac{0}{2} = 0 \quad (\text{not a natural number}) \] ### Step 5: Collect valid pairs From the calculations above, the valid pairs \((x, y)\) where both \( x \) and \( y \) are natural numbers are: - \( (2, 3) \) - \( (4, 2) \) - \( (6, 1) \) ### Step 6: Identify the domain The values of \( x \) that correspond to valid pairs are: - \( x = 2 \) - \( x = 4 \) - \( x = 6 \) Thus, the domain \( R \) is: \[ R = \{ (2, 3), (4, 2), (6, 1) \} \] The values of \( x \) in the domain are \( 2, 4, 6 \). ### Final Answer The domain of \( R \) is: \[ \{2, 4, 6\} \]
Promotional Banner

Similar Questions

Explore conceptually related problems

Let N be the set of natural numbers and the relation R be defined on N such that R={(x,y):y=2x,x,y in N} What is the domain,codomain and range of R? Is this relation a function?

The domain of relation R = {(x,y) : x^(2) + y^(2) = 16, x, y in Z } is

Let R be a relation on the set of natural numbers N, defined as: R={(x,y):y=2x,x,y in N}. Is R a function from N xxN ? If yes find the domain, co-domain and range of R.

Let R be a relation on the set of natural numbers ,defined as R ={(x,y):x+2y=20, x,y varepsilon N} and x varepsilon {1,2,3,4,5} .Then ,the range of R is :

Let A={1,2,3,4,….,14} Define a relation R from a set A to A by R={(x,y):2x-y=0, x,y in A} Write down its domain and range.

If A={2,4,6,8} and B={1,3,5}, then find the domain and range of the relation: R{(x,y):x in A, y in B and x gt y}