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The minimum value of x/(logx) is:...

The minimum value of `x/(logx)` is:

A

e

B

`1/e`

C

1

D

None of these

Text Solution

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The correct Answer is:
To find the minimum value of the function \( F(x) = \frac{x}{\log x} \), we will follow these steps: ### Step 1: Define the function Let \( F(x) = \frac{x}{\log x} \). ### Step 2: Differentiate the function To find the critical points, we need to differentiate \( F(x) \). We will use the quotient rule for differentiation, which states that if \( F(x) = \frac{U}{V} \), then: \[ F'(x) = \frac{U'V - UV'}{V^2} \] Here, \( U = x \) and \( V = \log x \). Calculating the derivatives: - \( U' = 1 \) - \( V' = \frac{1}{x} \) Now applying the quotient rule: \[ F'(x) = \frac{(1)(\log x) - (x)(\frac{1}{x})}{(\log x)^2} = \frac{\log x - 1}{(\log x)^2} \] ### Step 3: Set the derivative to zero To find the critical points, we set \( F'(x) = 0 \): \[ \frac{\log x - 1}{(\log x)^2} = 0 \] This implies that: \[ \log x - 1 = 0 \implies \log x = 1 \] ### Step 4: Solve for \( x \) From \( \log x = 1 \), we can exponentiate both sides to find \( x \): \[ x = e \] ### Step 5: Verify if it is a minimum To confirm that this critical point is a minimum, we can check the second derivative or analyze the sign of the first derivative around \( x = e \). However, since we are looking for the minimum value, we can directly evaluate \( F(x) \) at \( x = e \). ### Step 6: Calculate the minimum value Now we substitute \( x = e \) into the original function: \[ F(e) = \frac{e}{\log e} \] Since \( \log e = 1 \): \[ F(e) = \frac{e}{1} = e \] ### Conclusion Thus, the minimum value of \( \frac{x}{\log x} \) is \( e \).
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