Home
Class 12
MATHS
What is the domain of the function cos^(...

What is the domain of the function `cos^(-1)(2x-1)`?

A

`(-1,0)`

B

(0,1)

C

[0,1]

D

(0,-1)

Text Solution

AI Generated Solution

The correct Answer is:
To find the domain of the function \( \cos^{-1}(2x - 1) \), we need to determine the values of \( x \) for which the expression \( 2x - 1 \) lies within the range of the inverse cosine function. The inverse cosine function, \( \cos^{-1}(y) \), is defined for \( y \) in the interval \([-1, 1]\). ### Step-by-Step Solution: 1. **Set up the inequality**: Since \( \cos^{-1}(2x - 1) \) is defined when \( 2x - 1 \) is between -1 and 1, we can write the inequality: \[ -1 \leq 2x - 1 \leq 1 \] 2. **Solve the left part of the inequality**: Start with the left side: \[ -1 \leq 2x - 1 \] Add 1 to both sides: \[ 0 \leq 2x \] Divide by 2: \[ 0 \leq x \] This simplifies to: \[ x \geq 0 \] 3. **Solve the right part of the inequality**: Now, solve the right side: \[ 2x - 1 \leq 1 \] Add 1 to both sides: \[ 2x \leq 2 \] Divide by 2: \[ x \leq 1 \] 4. **Combine the results**: From the two parts of the inequality, we have: \[ 0 \leq x \leq 1 \] This means that \( x \) can take any value from 0 to 1, inclusive. 5. **Write the domain in interval notation**: The domain of the function \( \cos^{-1}(2x - 1) \) is: \[ [0, 1] \] ### Final Answer: The domain of the function \( \cos^{-1}(2x - 1) \) is \( [0, 1] \).
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the domain of the function cos^(-1)(3x-1)

What is the domain of the function sin ^(-1)x?

What is the domain of the function f(x)=(1)/(x-2) ?

The domain of the function f(x)=cos^(-1)(x-[x]) is

The domain of definition of cos^(-1)(2x-1) is

The domain of the function |x-1| is

Find the domain of the function f(x)=sin^(-1)(2x-3)

Find the domain of the function f(x)=sin^(-1)(2x-3)

The domain of the function f(x)=1/(x-1) is

The domain of the function cosec^(-1)((1+x)/x) is :