If x = a sec theta , y =b tan theta , th...

If `x = a sec theta , y =b tan theta ,` then `(d^2y)/(dx^2)` at `theta = pi/6` is :

A

`(-3sqrt3b)/a^2`

B

`(-2sqrt3b)/a`

C

`(-3sqrt3b)/a`

D

`(-b)/(3sqrt3a^2)`

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The correct Answer is:

A

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