(sin theta-cos theta+1)/(sin theta+cos t...

`(sin theta-cos theta+1)/(sin theta+cos theta-1)=?`

A

`sec theta -tan theta`

B

`sec theta tan theta`

C

`sec theta sin theta`

D

`sec theta + tan theta`

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The correct Answer is:

D

(sin theta-cos theta+1)/(sin theta+cos theta-1)=?
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