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Find the equation to a circle of radius ...

Find the equation to a circle of radius r which touches the axis of y at a point distant h from the origin, the centre of the circle being in the positive quadrant
Prove also that equation to the other tangent which passes through the origin is
` ( r ^(2) - h^(2)) x + 2rhy = 0`

Text Solution

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The correct Answer is:
` ( x - r)^(2) + ( y - h) ^(2) = r^(2)`
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