A conductivity cell is filled with 0.05 M NaOH solution offerin If the cell constant of the cell is `0.367 "cm"^(-1)`, calculate the following . The value of molar conductance:
A
`232.20 Omega^(-1)cm^(2)"mol"^(-1)`
B
`23.22 Omega^(-1)cm^(2)"mol"^(-1)`
C
`119.07 Omega^(-1)cm^(2)"mol"^(-1)`
D
`165.36 Omega^(-1)cm^(2)"mol"^(-1)`
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