Home
Class 12
CHEMISTRY
A solution containing 2g of anhydrous ba...

A solution containing 2g of anhydrous barium chloride in `400 cm^3` of water has a specific conductivity of `0.0058 "S cm"^(-1)` (at. wt. of Ba= 137, Cl = 35.5)
What is the molarity of the above solution?

A

0.204 M

B

0.024 M

C

0.420 M

D

4.021 M

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2022 TERM 1

    ICSE|Exercise question|1 Videos
  • PROLEMS BASED ON CHEMICAL STRUCTURES AND REACTIONS

    ICSE|Exercise QUESTIONS|185 Videos
  • SAMPLE PAPER 3 (CHEMISTRY)

    ICSE|Exercise QUESTIONS|70 Videos

Similar Questions

Explore conceptually related problems

The specific conductivity of a solution containing 5g of anhydrous BaCl_(2) (mol.wt. = 208) in 1000 cm^(3) of a solution is found to be 0.0058 "ohm"^(-1) cm^(-1) . Calculate the molar and equivalent conductivity of the solution.

The specific conductivity of a solution containing 1.0g of anhydrous BaCl_(2) in 200 cm^(3) of the solution has been found to be 0.0058 S cm^(-1) . Calculate the molar and equivalent conductivity of the solution. Molecular wt. of BaCl_(2) = 208

Calculate the molality of a solution containing 5.3 g of anhydrous Na_(2)CO_(3) in 400 g of water,

Molar conductivity of 0.15 M solution of KCI at 298 K, if its conductivity is 0.0152 S cm^(-1) will be

Conductivity of a solution containing one gram of anhydrous BaCl_(2) in 200 mL of the solution has been found to be 0.00585 "ohm"^(-) cm^(-) . Calculate the equivalent as well as molar conductance.

The conductivity of 0.01 mol L^(-1) KCl solution is 1.41xx10^(-3)" S "cm^(-1) . What is the molar conductivity ( S cm^(2) mol^(-1) ) ?

The specific conductivity of 0.5N solution is 0.01287 ohm^(-1) cm^(-1) . What would be its equivalent conductance?

Specific conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm^(-1) . Calculate its molar conductivity.

A solution containing 1g of sodium chloride in 100g of water freezes at - 0.604^@C . Calculate the degree of dissociation of sodium chloride. (Na = 23, Cl = 35.5, Kf for water = 1.87 k "mol"^(-1) )

The conductivity of 0.10 M solution of KCl at 298 K is 0.025 S cm Calculate its molar conductivity.