When radiation of wave length `lamda` is incident on a metallic surface, the stopping potential is 4.8Volt. If the same surface is illuminated with radiation of double the wavelength, then the stopping potential becomes 1.6V. Then the threshold wave length for the surface is

When radiation of the wavelength lamda is incident on a metallic surface ,the stopping potential is 4.8 V. If the same surface is illuminated with radiation of double the wavelength ,then the stopping potential becomes 1.6 V.Then the threshold wavelength for the surface is

When radiation of wavelength lambda is used to illuminate a metallic surface , the stopping potential is V. When the same suface is illuminated with radiation of wavelength 3 lambda the stopping is V/4 . If the therehold wavelength for the metallic

When a metalic surface is illuminated with light of wavelength lambda, the stopping potential is V. the same surface is illuminated by light of wavelength 2lambda the stopping potential is (V)/(3) The thershold waelength for the surface is

When a metallic surface is illuminated with radiation of wavelength lambda , the stopping potential is V . If the same surface is illuminated with radiation of wavelength 2 lambda , the stopping potential is (V)/(4) . The threshold wavelength surface is : (a) 5lambda (b) (5)/(2)lambda (c) 3lambda (d) 4lambda

When a centimeter thick surface is illuminated with light of wavelength lamda , the stopping potential is V. When the same surface is illuminated by light of wavelength 2lamda , the stopping potential is (V)/(3) . Threshold wavelength for the metallic surface is

When a surface 1 cm thick is illuminated with light of wavelength lambda , the stopping potential is V_(0) , but when the same surface is illuminated by light of wavelength 3lambda , the stopping potential is (V_(0))/(6) . Find the threshold wavelength for metallic surface.

When a piece of metal is illuminated by monochromatic light of wavelength lambda, then stopping potential is 3V_(s) . When the same surface is illuminated by the light of wavelength 2lambda , then stopping potential becomes V_(s) . The value of threshold wavelength for photoelectric emission will be

When a certain metallic surface is illuminated with monochromatic light of wavelength lamda , the stopping potential for photoelectric current is 3V_0 and when the same surface is illuminated with light of wavelength 2lamda , the stopping potential is V_0 . The threshold wavelength of this surface for photoelectrice effect is

When light of wavelength lambda is incident on a metal surface, stopping potential is found to be x. When light of wavelength n lambda is incident on the same metal surface, stopping potential is found to be (x)/(n+1) . Find the threshold wavelength of the metal.

When a metallic surface is illuminated by a monochromatic light of lamda the stopping potential for photoelectric current is 4V_(0) when the same surface is illuminated by light of wavelength 3 lamda the stopping potential is V_(0) The threshold wavelength for this surface for photoelectric effect is -