Home
Class 11
PHYSICS
A submarine is floating at a depth of 10...

A submarine is floating at a depth of 1000 meter in an ocean. The force on window having dimensions 20cm `**`20cm ,of submarine is (density of sea water =`1.03**10^(3)kgm^(-3)` and ignore atmospheric pressure)

Promotional Banner

Similar Questions

Explore conceptually related problems

The force acting on a window of are 50 xx 50 cm of a submarine at a depth of 2000 m in an ocean ,the interior of which is maintained at sea level atmospheric pressure is (density of sea water = 10 ^(3) kg m^(-3) ,g = 10 m s^(-2) )

At a depth of 500m in an ocean (a) what is the absolute pressure? (b) What is the gauge pressure? Density of sea water is 1.03 xx 10^(3) kg//m^(3), g=10ms^(-2) . Atmospheric pressure = 1.01 xx 10^(5)Pa .

At a depth of 1000 m in an ocean (a) what is the absolute pressure? (b) what is the gauge pressure? (c ) Find the force acting on the window of area 20 cm xx 20cm of a submarine at this depth, the interior of which is maintained at sea-level atmospheric pressure. The density of sea water is 1.03 xx 10^(3) kg m^(-3) , g=10ms^(-2) . Atmospheric pressure = 1.01 xx 10^(5) Pa .

What is the pressure in an ocean at a depth of 1000 m, if the density of water is 1.024xx 10^(3) (kg)/m^(3) . Atmospheric pressure P. = 1.01 xx 10^(5) Pa.

Iceberg floats in sea water with a part of it submerged. The percentage fraction of the ice berg not submerged is (density of ice = 0.9 g cm^(-3) , density of sea water = 1.1 g cm^(-3) )

Density of water is ...… ("10 g cm"^(-3)//"1 g cm"^(-3)) .

An air bubble rises the bottom of a lake to the top and increases thereby its volume 15 times . If the atmospheric pressure is 75 cm of hg and density of lake water is 1.02 xx10^(3) kg//m^(3) then find the depth of lake ( Neglect surface tension).

A tank contains water and mercury as shown in figure. An iron cube of edge d=6 cm is in equilibrium as shown. (density of iron =7.8xx10^(3) kg//m^(3) , density of mercury =13.6xx10^(3) kg//m^(3) , density of water =10^(3) kgm^(3) )(Neglect the atmospheric pressure) Time period of small oscillations of block is

At what depth below the surface of water will pressure be equal to twice the atmospheric pressure ? The atmospheric pressure is 10N cm^(-2) , density of water is 10^(3)kg m^(-3) and g=9.8 ms^(-2) .

A submarine experiences a pressure of 5.05xx10^(6)Pa at a depth of d_(1) in a sea When it goes futher to a depth of d_(2) . It experiences a pressure of 8.08xx10^(6)Pa . The d_(2)-d_(1) is approximately (density of water =10^(3)kg//m^(3) and acceleration due to gravity =10ms^(-2))