A particle executes SHM of type x=asinωt. It takes time t1 from x=0 to x=a/2 and t2 from x=a/2 to x=a. the ratio t1/t2

A particle executes SHM in accordance with x=A"sin"omegat . If t_(1) is the time taken by it to reach from x=0 to x=sqrt(3)(A//2) and t_(2) is the time taken by it to reach from x=sqrt(3)//2 A to x=A , the value of t_(1)//t_(2) is

A particle executes S.H.M. between x = -A and x = + A . The time taken for it to go from 0 to A/2 is T_(1) and to go from A/2 to A is T_(2) . Then

Find the time taken by the particle in going from x = (A)/2) to x=A Hint : Time taken to go from x=0 to x =A Time taken to go from x=0 to x= (A)/(2) Required time = t_(1) - t_(2)

A particle startsits SHM at t=0 . At a particular instant on its way to extreme position , x= (A)/(2) . Find the time taken by the particle to come back to this point after passing through the extreme position. Hint : t_(1) = time taken to go from x=0 to x= (A)/(2) t_(2) = time taken to go to extreme position and come back to mean position = (T)/(2) Required time = (T)/(2) - t_(1)

A particle performs SHM about x=0 such that at t=0 it is at x=0 and moving towards positive extreme. The time taken by it to go from x=0 to x=(A)/(2) is____ time the time taken to go from x=(A)/(2) to A . The most suitable option for the blank space is

A particle executes SHM according to equation x=10(cm)cos[2pit+(pi)/(2)] , where t is in seconds. The magnitude of the velocity of the particle at t=(1)/(6)s will be :-

Assertion : A particle is under SHM along the x - axis. Its mean position is x = 2 , amplitude is A = 2 and angular frequency omega . At t = 0 , particle is at origin, then x - co-ordinate versus time equation of the particle will be x = -2 cos omega t + 2 . Reason : At t = 0 , particle is at rest.

Two particles are executing SHM in a straight line. Amplitude A and the time period T of both the particles are equal. At time t=0, one particle is at displacement x_(1)=+A and the other x_(2)=(-A/2) and they are approaching towards each other. After what time they across each other? T/4

x and y co-ordinates of a particle moving in x-y plane at some instant of time are x=2t and y=4t .Here x and y are in metre and t in second. Then The distance travelled by the particle in a time from t=0 to t=2s is ……… m