Home
Class 12
PHYSICS
The dipole moment of a coil of area A an...

The dipole moment of a coil of area A and number of turns N and carrying current I will be

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the magnetic dipole moment of the spiral of total number of turns N, carrying current I having inner and outer radii v and b respectively

(a) Write the expression for the equivalent megnetic moment of a planer current loop of area A, having N turns and carrying a current i. Use the expression to find the magentic dipole moment of a revolving electron ? (b) A circuit loop of radius r, having N turns and carrying current I, is kept in the XY plane. It is then subjected to a uniform magnetic field vec(B)=B_(x)hat(i)+B_(y)hat(j)+B_(z)hat(k) . Obtain expression for the magnetic potential energy of the coil-magnetic field system.

A circular coil of radius r having number of turns n and carrying a current A produces magnetic induction at its centre of magnitude B. B can be doubled by

Obtain an expression for magnetic flux density B at the centre of a circular coil of radius R, having N turns and carrying a current I.

Current is flowing in a coil of area A and number of turns N, then magnetic moment of the coil ,M is equal to

The magnetic moment of a current I carrying circular coil of radius r and number of turns N varies as

Consider a coil (of area A, resistance R and number of turns N) held perpendicular to a uniform magnetic field of strength B. The coil is now turned through 180^(@) in time Deltat . What is (i) Average induced emf (ii) Average induced current (iii) Total charge that flows through a given cross-section of the coil?

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B_(1) . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B_(2) . The ratio (B_(1))/(B_(2)) is:

The effective radius of a circular coil is R and number of turns is N. The current through it is i ampere. The work done is rotating the coil from angle theta = 0^(@) to theta = 180^(@) in an external magnetic field B will be -