4g of He and ngm of `CO_(2)` at `25^(@)C` have same kinetic energy.What is the value of n

Average K.E. of CO_(2) at 27^(@)C is E. the average kinetic energy of N_(2) at the same temperature will be

Average K.E. of CO_(2) at 27^(@)C is E. the average kinetic energy of N_(2) at the same temperature will be

8g each of oxygen and hydrogen at 27^(@)C will have the total kinetic energy in the ratio of …….

Two bodies of masses m_(1) and m_(2) have same kinetic energy. The ratio of their momentum is

An electron, a doubly ionized helium ion (He^(+ +)) and a proton are having the same kinetic energy . The relation between their respectively de-Broglie wavelengths lambda_e , lambda_(He^(+)) + and lambda_p is :

H^(+), He^(+) and O^(++) all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity . The masses of H^(+), He^(+) and O^(2+) are 1 amu, 4 amu and 16 amu respectively . Then

The only force acting on a 2.0-kg body as it moves along the x-axis varies as shown in figure. The velocity of the body at x=0 is 4.0ms^-1 . a. What is the kinetic energy of the body at x=3.0m ? b. At what value of x will the body have a kinetic energy of 8.0J ? c. What is the maximum kinetic energy attained by the body between x=0 and x=5.0m ?

4 moles CO, 5 moles N_2 and 2 mole C_2H_4 are placed in a 5 litre vessel at 27^@C . The ratio of kinetic energy per molecule of CO_2, He and NH_3 is

Solid Sphere, Ring and Disc having same mass m and radius r the smallest kinetic energy at the bottom of the incline will be achieved by 1)Solid Sphere 2)Ring 3)Disc 4)All will achieve the same kinetic energy

Assertion: A light body and a heavy body have same momentum. Then they also have same kinetic energy. Reason: Kinetic energy does not depand on mass of the body.