The volume of oxygen liberated from 15 ml of 20 volume `H_(2)O_(2)` is

The volume of oxygen gas liberated at NTP from 30 mL of 20 (V H_2O_2) , solution is

The volume of oxygen liberated from 0.68g of H_(2)O_(2) is

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " "of" H_(2)O_(2) "solution" =2xx "molarity of" H_(2)O_(2) solution 20mL of H_(2)O_(2) solution is reacted with 80 mL of 0.05 MKMnO_(4) "in acidic medium then what is the volume strength of" H_(2)O_(2) ?

When steam is passed over hot iron, hydrogen is liberated and Fe_(3)O_(4) is formed according to the chemical equation 3 Fe + 4 H_(2)O to Fe_(3)O_(4) + 4 H_(2)(g) . In a typical reaction, 56 g iron was consumed. Calculate the following: The volume of H_(2) liberated at STP (when molar volume of H_(2) " is " 22.4 L )

The volume of O_(2) liberated from 0.96g of H_(2)O_(2) is

The volume of O_(2) liberated from 0.96g of H_(2)O_(2) is

100 mL of ozone at STP was passed through 100 mL of 10 volume H_(2)O_(2) solution. What is the volume strength of H_(2)O_(2) after attraction?

What do you mean by 15 volume H_(2)O_(2) solution?

During electrolysis of water, the volume of oxygen liberated is 2.24 dm^(3). The volume of hydrogen liberated, under same conditions will be

Calculate the volume of oxygen required for the complete combustion of 20 ml of propane (C_(3)H_(8)) C_(3)H_(8)+5O_(2)to3CO_(2)+4H_(2)O